a: \(\widehat{BAC}=180^0-80^0-40^0=60^0\)
\(\widehat{CAD}=\dfrac{60^0}{2}=30^0\)
=>\(\widehat{ADC}=180^0-30^0-40^0=110^0\)
b: Xét ΔABD và ΔAED có
AB=AE
\(\widehat{BAD}=\widehat{EAD}\)
AD chung
Do đó: ΔABD=ΔAED
cho ΔABC vuong tai A va ABC=60
a, so sanh AB va AC
b, Tren BC lay D sao cho BD =AB. Qua D dung cac duong thang vuong goc voi BC cat tia doi AB tai E. CHung minh ΔABC=ΔDEB
c, goi H la giao diem cua ED va AC. chung minh BH la tia phan giac cua ABC
d,Qua B dung cac duong thang vuong goc voi AB cat duong thang ED tai K vhng minh ΔHBK deu
cho tam giac ABC can tai A co A < 90 do, duong vuong goc voi AB tai B va duong thang vuong goc voi AC tai C va chung cat nhau tai M.
a, c/m tgABM = tgACM, AM la phan giac cua goc BAC
b, Qua M ve duong thang song song voi AC, duong thang nay cat AB o D. Tren tia doi cua tia CA lay diem E sao cho CE = DB, c/m tgDBM = tgECM
c, BC cat DM tai F. c/m DF = CE
Cho ΔABC vuong tai C. Tren canh BC lay diem Dsao cho AD =AB. ke qua D duong thang vuong goc voi AB cat BC tai E. AE cat CD tai I. chung minh
a, AE la tia phan giac CAB
b, AD la trung truc cua CD
c, so sanh CD va BC
d, M la trung diem cua BC, DM cat BI tai G, CG cat DB tai K. chung minh K la trung diem cua DB
Cho \(\Delta ABC\) vuoong tai A, tren canh BC lay diem M sao cho BM=MA, tia phan giac cua goc B cat AC o N
a/ Chung minh: a1/NA=NM
a2/NM\(\perp BC\)
a3/Goc \(BAM=C+MAC\)
b/\(\Delta ABC\) can co them dieu kien gi ve goc thi M la trung diem cua BC
cho tam giac abc co ^A=90 do .ke tia phan giac goc B cat AC tai D \(\left(E\in BC\right)\) sao cho BE=BA
a, chung minh DA=DE va DE vuong goc voi BC
b, ED cat BA tai K.chung minh DF = DC
c, chung minh BD vuong goc voi FC
cho goc nhon xOy tren tia Ox lay hai diem A;B sao cho OA nho hon OB tren tia Oy lay hai diem C;D sao cho OC nho hon OD .Biet OA=OC;OB=OD va AD cat BC tai E
a. chung minh : tam giac EAB= tam giac ECD
b. chung minh : OE la tia phan giac cua goc xOy
c. chung minh AC song song voi BD
cho Ot la tia phan giac cua goc nhon xoy. Tren tia Ox lay diem A, tren tia Oy lay diem B saocho OA=OB. Tren tia Ot lay diem M sao cho OM>OA.a) Chung minh tam giac AOM= tam giac BOM. b) Goi C la giao diem cua tia Am va tia Oy. D la giao diem cua BM va Ox. Chung minh rang: AC=BD. c) Noi a voi B, ve duong thang d vuong goc voi AB tai A. Chung minh:d// Ot
Cho tam giac deu ABC. Tren canh AB lay diem D sao cho AD=1/3 AB. Tu D ke duong thang vuong goc AB cat A o E, qua E ke duong thang vuong goc AC cat BC o F. Chung minh. a, DF vuong goc BC. b, Tam giac DEF la tam giac deu
cho tam giac MNP vuong tai M co MN =3cm MP= 4cm
a. tinh NP
b,tia phan giac goc N cat canh MP tai Q .ke Q vuong goc NP tai K .chung minh tam giac MNQ =tam giac KNQ
c,goi giao diem cua KQ va MN la H . chung minh tam giac NHP can
d, chung minh MQ nho hon QP <cac ban ve hinh cho minh lun nha .>
