Zn +2HCl--->ZnCl2 +H2
a) Ta có
m\(_{HCl}=\frac{200.20}{100}=40\left(g\right)\)
n\(_{HCl}=\frac{40}{36,5}=1\left(mol\right)\)
Theo pthh
n\(_{Zn}=\frac{1}{2}n_{HCl}=0,5\left(g\right)\)
m\(_{Zn}=0,5.65=32,5\left(g\right)\)
b) Theo pthh
n\(_{ZnCl2}=\frac{1}{2}n_{HCl}=0,5\left(mol\right)\)
m\(_{ZnCl2}=0,5.136=68\left(g\right)\)
mdd= 200+32,5-1=231,5(g)
C%=\(\frac{68}{231,5}.100\%=29,37\%\)
Chúc bạn học tốt
Zn + 2HCl = ZnCl2 + H2
40/73....80/73......40/73......40/73
mHCl= 200.20%=40g
=> nHCl=80/73 mol
=> nZn=1/2 nHCl=40/73 mol
=> mZn=35,616 g
nZnCl2 =40/73 mol
=> mZnCl2=74,52 g
=> C%= 74,52:(35,616+200-40/73 .2) =31,76%
