Kẻ đoạn thẳng OC như hình sao cho: OC//aa' ; OC//bb'
Vì OC//aa' nên:\(\widehat{a'AO}=\widehat{AOC}=30^o\) (2 góc so le trong)
Vì OC//bb' nên: \(\widehat{OBb'}=\widehat{BOC}=45^o\) ( 2 góc so le trong)
\(\Rightarrow\widehat{AOB}=\widehat{AOC}+\widehat{BOC}=30^o+45^o=75^o\)