a) \(F\left(3\right)=-2\cdot3+3\)
\(=-6+3=-3\)
\(F\left(\frac{2}{5}\right)=-2\cdot\frac{2}{5}+3\)
\(=-\frac{4}{5}+\frac{15}{5}=\frac{11}{5}\)
b) Đặt F(x)=-5
\(\Leftrightarrow-2x+3=-5\)
\(\Leftrightarrow-2x=-8\)
hay x=4
Vậy: Khi x=4 thì F(x)=-5