Đề có sai không bạn?
Violympic toán 7
Các câu hỏi tương tự
Cho \(\frac{a^2+b^2}{c^2+d^2}=\frac{ab}{cd}\)
CMR \(\left[{}\begin{matrix}\frac{a}{b}=\frac{c}{d}\\\frac{a}{b}=\frac{d}{c}\end{matrix}\right.\)
Bài 1 : Cho 4 số a , b ,c khác 0 thỏa mãn \(^2=ac;c^2=bd;b^3+c^3+d^3\ne0\)
CMR : \(\frac{a^3+b^3+c^3}{b^3+c^3+d^3}=\frac{a}{d}\)
Bài 2 : Cho a , b , c , d > 0 . CMR :
\(1< \frac{a}{a+b+c}+\frac{b}{b+c+d}+\frac{c}{c+d+a}+\frac{d}{d+a+b}< 2\)
Cho tỉ lệ thức \(\frac{\overline{ab}}{\overline{bc}}=\frac{a}{c}\) CMR \(\frac{a^2+b^2}{b^2+c^2}=\frac{a}{c}\)
--\(Cho\frac{a}{b}=\frac{3}{4}.TínhA=\frac{a^2+3b^2}{a^2-3b^2}\)
--Cho\(\frac{x}{a+2b+c}=\frac{y}{2a+b-c}=\frac{z}{4a-4b+c}\)
CMR \(\frac{a}{x+2y+z}=\frac{b}{2x+y-z}=\frac{c}{4x-4y+z}\)
Please HELP meeeeeee🙏 🙏 🙏 🙏
cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\)
cmr \(\frac{ab}{cd}=\frac{a^2-b^2}{c^2-d^2}\)
cho frac{a}{b}frac{c}{d}chung minh rang:
frac{a}{a-b}frac{c}{c-d} frac{a}{b}frac{a+c}{b+d} frac{a}{3a+b}frac{c}{3c+d}
frac{a.b}{c.d}frac{left(a-bright)^2}{left(c-dright)^2} frac{a.c}{b.d}frac{a^2+c^2}{b^2+d^2}frac{a.c}{b.d}frac{a^2-c^2}{b^2-d^2}
Đọc tiếp
cho \(\frac{a}{b}=\frac{c}{d}\)chung minh rang:
\(\frac{a}{a-b}=\frac{c}{c-d}\) \(\frac{a}{b}=\frac{a+c}{b+d}\) \(\frac{a}{3a+b}=\frac{c}{3c+d}\)
\(\frac{a.b}{c.d}=\frac{\left(a-b\right)^2}{\left(c-d\right)^2}\) \(\frac{a.c}{b.d}=\frac{a^2+c^2}{b^2+d^2}\)\(\frac{a.c}{b.d}=\frac{a^2-c^2}{b^2-d^2}\)
Cho\(\frac{a}{b}=\frac{c}{d}\)chứng minh rằng:
a)\(\frac{a}{3a+b}=\frac{c}{3c+d}\)
b)\(\frac{a\times c}{b\times d}=\frac{a^2+c^2}{b^2+d^2}\)
c)\(\frac{a\times b}{c\times d}=\frac{a^2-b^2}{c^2-d^2}\)
CMR: \(\frac{a^2+b^2+c^2}{3}\ge\left(\frac{a+b+c}{3}\right)^2\)
Cho \(\frac{a}{c}=\frac{c}{b}\) . C/m rằng \(\frac{a^2+c^2}{b^2+c^2}=\frac{a}{b}\)