Question

Cho \(\frac{5x-2y}{x+3y}=\frac{7}{4}\)
Tính giá trị \(\frac{x}{y}\)

Answer 1

\(\frac{5x-2y}{x+3y}=\frac{7}{4}\)

=> (5x - 2y).4 = (x + 3y).7

=> 20x - 8y = 7x + 21y

=> 20x - 7x = 21y + 8y

=> 13x = 29y

=> \(\frac{x}{y}=\frac{29}{13}\)

Vậy \(\frac{x}{y}=\frac{29}{13}\)

Answer 2

\(\frac{5x-2y}{x+3y}=\frac{7}{4}\)

\(4\left(5x-2y\right)=7\left(x+3y\right)\)

\(20x-8y=7x+21y\)

\(20x-7x=21y+8y\)

\(13x=29y\)

\(\frac{x}{y}=\frac{29}{13}\)