\(a+b+c=abc\Rightarrow\frac{a+b+c}{abc}=1\)
\(\Rightarrow Q=\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca}=1\)
\(P=\frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}=\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)^2-2\left(\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca}\right)\)
\(\Rightarrow P=3^2-2.1=7\)