Question

Cho em hỏi em sai chỗ nào vậy ạ!  

Tính:\(\lim\limits_{\rightarrow+\infty}\dfrac{n^3}{n^2}\)

Ta có:

\(\lim\limits_{\rightarrow+\infty}n^3=+\infty\)

\(\lim\limits_{\rightarrow+\infty}\dfrac{1}{n^2}=0\)

\(\Rightarrow\lim\limits_{\rightarrow+\infty}\dfrac{n^3}{n^2}=0\)

Answer 1

Ở chỗ dấu \(\Rightarrow\) cuối cùng ; \(\lim\limits_{x\rightarrow+\infty}\dfrac{n^3}{n^2}=+\infty\)

Answer 2

Ta có: \(lim_{\rightarrow+\infty}=\dfrac{n^3}{n^2}\)

\(lim_{\rightarrow+\infty}=\dfrac{n^2n}{n^2}\)
\(lim_{\rightarrow+\infty}=n=+\infty\)