a: \(C=\dfrac{2x-9}{\left(x-2\right)\left(x-3\right)}-\dfrac{x+3}{x-2}+\dfrac{2x+1}{x-3}\)
\(=\dfrac{2x-9-x^2+9+2x^2-4x+x-2}{\left(x-3\right)\left(x-2\right)}\)
\(=\dfrac{x^2-x-2}{\left(x-3\right)\left(x-2\right)}=\dfrac{x+1}{x-3}\)
b: Để C là số nguyên thì \(x-3+4⋮x-3\)
=>\(x-3\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(x\in\left\{4;5;1;7;-1\right\}\)