a: ĐKXĐ: \(x\notin\left\{1;-1\right\}\)
b: \(C=\dfrac{x}{2\left(x-1\right)}-\dfrac{x^2+1}{2\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x^2+x-x^2-1}{2\left(x-1\right)\left(x+1\right)}=\dfrac{1}{2\left(x+1\right)}\)
c: Để C=-1/2 thì 2(x+1)=-2
=>x+1=-1
hay x=-2(nhận)