a: ĐKXĐ: a>=0; a<>1
b: \(A=\dfrac{a+\sqrt{a}-2-a+\sqrt{a}+2}{\left(\sqrt{a}+1\right)\left(\sqrt{a}-1\right)}\cdot\dfrac{\sqrt{a}+1}{1}\)
\(=\dfrac{2\sqrt{a}}{\sqrt{a}-1}\)
c: Để A là số nguyên thì \(2\sqrt{a}-2+2⋮\sqrt{a}-1\)
=>\(\sqrt{a}-1\in\left\{1;-1;2\right\}\)
=>\(a\in\left\{4;0;9\right\}\)