\(lim\frac{an^2+a^2n+1}{n^2+2n+1}=lim\frac{a+\frac{a^2}{n}+\frac{1}{n^2}}{1+\frac{2}{n}+\frac{1}{n^2}}=a\)
\(\Rightarrow a=a^2-a+1\Leftrightarrow\left(a-1\right)^2=0\Rightarrow a=1\)
Chương 4: GIỚI HẠN
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tính các giới hạn sau :a/ \(lim\dfrac{3x^2 3}{x 1}\left(x\rightarrow1\right)\)b/ \(lim\dfrac{2^n 2.4^n}{4.4^n-3.2^n}\)c/ \(lim\dfrac{\left(2n^2 1\right)\left(2n^5 n\right)}{n^7 2}\)d/ \(lim\dfrac{2x 1}{\left(x-2\right)^2}\left(x\rightarrow2\right)\)e...
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tính các giới hạn sau:
a, lim\(\frac{n^{2020}-n+1}{n^{2022}+2n-3}\)
b, lim(\(\sqrt[3]{n^3-2n^2}-n\))
c, lim \(\left(\sqrt{n^2+3n}-n+2\right)\)
d, lim \(n\left(\sqrt{n^2-1}-\sqrt{n^2+2}\right)\)
Tìm giới hạn dãy số sau
\(lim\dfrac{\left(2n-1\right)\left(3n^2+2\right)^3}{-2n^5+4n^3-1}\)
\(lim\left(3.2^{n+1}-5.3^n+7n\right)\)
tim giới hạn :
lim\(\frac{2n^3+3n^2-n+5}{\left(n^2+n+1\right)\left(n^2+2\right)}\)
Tìm các giới hạn sau:
a) \(\lim\limits\left(\sqrt{2n^2+3}-\sqrt{n^2+1}\right)\)
b) \(\lim\limits\dfrac{1}{\sqrt{n+1}-\sqrt{n}}\)
a; lim\(\frac{\sqrt{6n^4+n+1}}{2n^2+1}\)
b; lim \(\frac{\left(n+1\right)\left(2n+1\right)^2\left(3n+1\right)^3}{n^2\left(n+2\right)^2\left(1-3n\right)^2}\)
Tìm giới hạn lim un
a. \(u_n=\left(2-3n\right)^4\left(n+1\right)^3\)
b.\(u_n=\sqrt[3]{n+4}-\sqrt[3]{n+1}\)
c.\(u_n=\sqrt[3]{8n^3+3n^2+4}-2n+6\)
d. \(\sqrt[3]{8n^3+3n^2-2}+\sqrt[3]{5n^2-8n^3}\)
Help me ! Gợi ý cho mik cx đc ạ . Tks mng
tìm giới hạn:
lim\(\frac{n^2+2n-3}{n\left(n+1\right)}\)
a)lim \(\frac{\left(2n+1\right)^2\left(n-1\right)}{\sqrt[3]{n^3+7n-2}}\)
b)lim [(2n-1)\(\sqrt{\frac{2n^2+5}{n^4+n^2+2}}\)]
c)lim [n(\(\sqrt[3]{n^3+n^2}-n\))]