\(\dfrac{1+a+b}{2}\ge\dfrac{1+a+b+ab}{2+a+b}\)
\(\Leftrightarrow\left(1+a+b\right)\left(2+a+b\right)\ge2\left(1+a+b+ab\right)\)
\(\Leftrightarrow2+a+b+2a+a^2+ab+2b+ab+b^2\ge2+2a+2b+2ab\)
\(\Leftrightarrow a^2+b^2+2ab+3a+3b+2\ge2ab+2a+2b+2\)
\(\Leftrightarrow a^2+b^2+a+b\ge0\)