Question

Cho \(a=-6,b=3,c=-2\).

Tính :

                \(\left|a+b-c\right|,\left|a-b+c\right|,\left|a-b-c\right|\)

Answer 1

\(|a+b-c|\)=1

\(|a-b+c|\)=11

\(|a-b-c|\)=7

Answer 2

Đặt \(A=\left|a+b-c\right|\)

Thay \(a=-6,b=3,c=-2\) vào A, ta có:

\(A=\left|-6+3-\left(-2\right)\right|\)

\(A=\left|1\right|\)

\(A=1\)

Đặt \(B=\left|a-b+c\right|\)

Thay \(a=-6,b=3,c=-2\) vào B, ta có:

\(B=\left|-6-3+\left(-2\right)\right|\)

\(B=\left|-11\right|\)

\(B=11\)

Đặt \(C=\left|a-b-c\right|\)

Thay \(a=-6,b=3,c=-2\) vào C, ta có:

\(C=\left|-6-3-\left(-2\right)\right|\)

\(C=\left|-5\right|\)

\(C=5\)