Question

cho a=(-3x⁵y³)⁴; b=(2x²z⁴)⁵. Tìm x,y,z, biết A+B = 0

Answer 1

Ta có: \(A+B=0\)

\(\Leftrightarrow\left(-3x^5y^3\right)^4+\left(2x^2z^4\right)^5=0\)

\(\Leftrightarrow81x^{20}y^{12}+32x^{10}z^{20}=0\)

\(\Leftrightarrow x^{10}\left(81x^{10}y^{12}+32z^{20}\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x^{10}=0\\81x^{10}y^{12}+32z^{20}=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\y=0\\z=0\end{matrix}\right.\)

Vậy: (x,y,z)=(0;0;0)