\(A=16+10^{2015}+10^{2016}+10^{2017}+10^{2018}\)
Ta có :
\(10^x\) có dạng \(3k+1\)
\(\Leftrightarrow10^{2015}+10^{2016}+10^{2017}+10^{2018}=\left(3k+1\right).4=12k+1\)
Mà \(16=3k+1\)
\(\Leftrightarrow A=\left(12k+1\right)+\left(3k+1\right)\)
\(\Leftrightarrow A=3k+1\)
\(\Leftrightarrow A\) ko là số chính phương