Ta có: \(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(m_{Cl}=m_{muối}-m_{khối.lượng}=19,95-9,3=10,65\left(g\right)\)
\(\Rightarrow n_{H_2}=\frac{1}{2}n_{HCl}=\frac{1}{2}n_{Cl}=0,15\left(mol\right)\)
\(\Rightarrow V_{H_2}=n.22,4=0,15.22,4=3,36\left(l\right)\)
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