Ta có: \(n_{Cl^-}=n_{NaCl}=\frac{5}{58,5}=\frac{10}{117}\left(mol\right)\)
PT ion: \(Cl^-+Ag^+\rightarrow AgCl_{\downarrow}\)
_____10/117__________10/117 (mol)
\(\Rightarrow m_{\downarrow}=m_{AgCl}=\frac{10}{117}.143,5\approx12,26\left(g\right)\)
Bạn tham khảo nhé!