\(n_{KOH}=0.4\cdot2=0.8\left(mol\right)\)
\(2KOH+H_2SO_4\rightarrow K_2SO_4+H_2O\)
\(0.8..............0.4............0.4\)
\(V_{dd_{H_2SO_4}}=\dfrac{0.4}{0.5}=0.8\left(l\right)\)
\(C_{M_{K_2SO_4}}=\dfrac{0.4}{0.4+0.8}=0.33\left(M\right)\)
\(2KOH+H2SO4\rightarrow K2SO4+2H2O\)
\(n_{KOH}=0,4.2=0,8\left(mol\right)\)
Theo PT:
\(n_{H2SO4}=n_{K2SO4}=\dfrac{1}{2}n_{KOH}=0,4\left(mol\right)\)
\(\Rightarrow V_{H2SO4}=\dfrac{0,4}{0,5}=0,8\left(l\right)\)
\(V_{dd}saupư_{K2SO4}=0,4+0,8=1,2\left(l\right)\)
\(C_{M\left(K2SO4\right)}=\dfrac{0,4}{1,2}=\dfrac{1}{3}\left(M\right)\)
