\(\frac{3x-y}{x+y}=\frac{3}{4}\)
\(\left(3x-y\right)4=\left(x+y\right)3\)
\(12x-4y=3x+3y\)
\(12x-3x=3y+4y\)
\(9x=7y\)
\(\frac{x}{y}=\frac{7}{9}\)
hay là \(\frac{3x-y}{x+y}=\frac{3}{4}\) này chắc đúng
Ta có: \(\frac{3x-y}{x+y}=\frac{3}{4}\)
=> 4(3x - y) = 3(x + y)
=> 12x - 4y = 3x + 3y
=> 12x - 3x = 3y + 4y
=> (12 - 3)x = (3 + 4)y
=> 9x = 7y
=> x/y = 7/9
Vậy x/y = 7/9