a. PTHH: CaCO3 + 2HCl ---> CO2 + H2O + CaCl2
b. Ta có: \(n_{CaCO_3}=\dfrac{30}{100}=0,3\left(mol\right)\)
Theo PT: \(n_{CO_2}=n_{CaCO_3}=0,3\left(mol\right)\)
=> \(V_{CO_2}=0,3.22,4=6,72\left(lít\right)\)
c. Theo PT: \(n_{CaCl_2}=n_{CaCO_3}=0,3\left(mol\right)\)
=> \(m_{CaCl_2}=0,3.111=33,3\left(g\right)\)