-Gọi số mol NaOH là x, số mol KOH là y
NaOH+HCl\(\rightarrow\)NaCl+H2O
x\(\rightarrow\)........x...........x
KOH+HCl\(\rightarrow\)KCl+H2O
y\(\rightarrow\)......y..........y
-Ta có hệ:\(\left\{{}\begin{matrix}40x+56y=3,04\\58,5x+74,5y=4,15\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,02\\y=0,04\end{matrix}\right.\)
mNaOH=0,02.40=0,8 gam
mKOH=0,04.56=2,24 gam