Theo gt:mCu:mFe=2:3
=>\(\left\{{}\begin{matrix}m_{Cu}=20:5.2=8\left(tấn\right)\\m_{Fe}=20:5.3=12\left(tấn\right)\end{matrix}\right.\)
Ta có PTHH:
2Cu+O2->2CuO
.8...............10......(tấn)
3Fe+2O2->Fe3O4
12.................16,57....(tấn)
Theo các PTHH:moxit=mCuO+\(m_{Fe_3O_4}\)=10+16,57=26,57(tấn)