a: Hai đường thẳng cắt nhau tạo thành 4 góc
b: Ta có: \(\widehat{xOy'}-\widehat{xOy}=30^0\)
mà \(\widehat{xOy'}+\widehat{xOy}=180^0\)
nên \(\left\{{}\begin{matrix}\widehat{xOy'}=105^0\\\widehat{xOy}=75^0\end{matrix}\right.\)
=>\(\widehat{x'Oy}=105^0;\widehat{x'Oy'}=75^0\)