a)A(x)=3x5-12x3-6x2+11x+9
B(x)=-3x5+12x3+7x2-9x-7
b)A(x)+B(x)=
3x5-12x3-6x2+11x+9
+
-3x5+12x3+7x2-9x-7
= x2+2x+2
Vậy C(x)=x2+2x+2
A(x)-B(x)=
3x5-12x3-6x2+11x+9
-
-3x5+12x3+7x2-9x-7
= 6x5-24x3-13x2+20x+16
Vậy D(x)=6x5-24x3-13x2+20x+16
c)C(x)=x2+2x+2=x2+2x+1+1=(x+1)2+1
Do (x+1)2\(\ge0\forall x\in R\)
=>C(x)=(x+1)2+1\(\ge1\forall x\in R\)
=>C(x)\(\ge0\forall x\in R\) =>C(x) vô nghiệm (đpcm)