a: \(\dfrac{A}{B}=\dfrac{2x^2-x+2}{2x+1}=\dfrac{2x^2+x-2x-1+3}{2x+1}\)
\(=x-1+\dfrac{3}{2x+1}\)
Vậy: Q=x-1; R=3
b: Để A chia hết cho B thì \(2x+1\in\left\{1;-1;3;-3\right\}\)
hay \(x\in\left\{0;-1;1;-2\right\}\)
c: \(x^3+x^2-x+2a⋮x-2\)
\(\Leftrightarrow x^3-2x^2+3x^2-6x+5x-10+2a+10⋮x-2\)
=>2a+10=0
hay a=-5