\(a,4Na+O_2\underrightarrow{t^o}2Na_2O\)
\(4:1:2\left(mol\right)\)
\(0,01:0,0025:0,005\left(mol\right)\)
\(n_{Na}=\dfrac{m}{M}=\dfrac{0,23}{23}=0,01\left(mol\right)\)
\(b,m_{Na_2O}=n.M=0,005.\left(23.2+16\right)=0,31\left(g\right)\)
\(c,V_{O_2}=n.22,4=0,0025.22,4=0,056\left(l\right)\)