Question

câu 6

Answer 1

=\(\lim\limits_{x->+\infty}\)\(\dfrac{x\left(1+\dfrac{3}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}\)=\(\lim\limits_{x\rightarrow+\infty}\)\(\dfrac{1+\dfrac{3}{x}}{1-\dfrac{2}{x}}\)=1