\(f\left(x\right)=\frac{6x^3+ax^2-34x+b}{3x^2-8x+11}=\frac{2x\left(3x^2-8x+11\right)+\left(a+16\right)x^2-56x+b}{3x^2-8x+11}=2x+\frac{\frac{a+16}{3}\left(3x^2-8x+11\right)+\left(\frac{a+16}{3}-56\right)x+b-\frac{11\left(a+16\right)}{3}}{3x^2-8x+11}\)
\(f\left(x\right)=2x+\frac{a+16}{3}+\frac{\left(\frac{a+16}{3}-56\right)x+b-\frac{11\left(a+16\right)}{3}}{3x^2-8x+11}\)
a, b phải thỏa mãn hệ
\(\left\{\begin{matrix}\frac{a+16}{3}-56=0\\b-\frac{11\left(a+16\right)}{3}=0\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}a=3.56-16=152\\b=11.56=616\end{matrix}\right. \)