\(a,\Leftrightarrow x=\left(-\dfrac{2}{3}\right)^5:\left(-\dfrac{2}{3}\right)^2=\left(-\dfrac{2}{3}\right)^3=-\dfrac{8}{27}\\ b,\Leftrightarrow\left(-\dfrac{1}{3}\right)^3\cdot x=\left(-\dfrac{1}{3}\right)^4\Leftrightarrow x=-\dfrac{1}{3}\\ c,\Leftrightarrow x-\dfrac{1}{2}=\dfrac{1}{3}\Leftrightarrow x=\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{5}{6}\\ d,\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{2}{5}\\x+\dfrac{1}{2}=-\dfrac{2}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{10}\\x=-\dfrac{9}{10}\end{matrix}\right.\\ e,\Leftrightarrow2^{x-1}=2^4\Leftrightarrow x-1=4\Leftrightarrow x=5\\ f,\Leftrightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)
