\(D=\left(a+b\right)\left(a+1\right)\left(b+1\right)\)
\(\Rightarrow D=3\left(a+1\right)\left(b+1\right)\)
\(\Rightarrow D=\left(3a+3\right)\left(b+1\right)\)
\(\Rightarrow D=3ab+3b+3a+3\)
\(\Rightarrow D=-15+3\left(a+b\right)+3\)
\(\Rightarrow D=-15+9+3\)
\(\Rightarrow D=-3\)
Vậy D = -3