a: \(F\left(-2\right)=\dfrac{3}{2}\cdot\left(-2\right)^2=\dfrac{3}{2}\cdot4=6\)
F(3)=3/2*3^2=27/2
\(F\left(\sqrt{5}\right)=\dfrac{3}{2}\cdot\left(\sqrt{5}\right)^2=\dfrac{3}{2}\cdot5=\dfrac{15}{2}\)
\(F\left(-\dfrac{\sqrt{2}}{3}\right)=\dfrac{3}{2}\cdot\dfrac{2}{9}=\dfrac{3}{9}=\dfrac{1}{3}\)
b: \(F\left(-2\right)=\dfrac{3}{2}\cdot\left(-2\right)^2=\dfrac{3}{2}\cdot4=6\)
=>A thuộc (P)
\(F\left(-\sqrt{2}\right)=\dfrac{3}{2}\cdot\left(-\sqrt{2}\right)^2=\dfrac{3}{2}\cdot2=3\)
=>B thuộc (P)
\(F\left(-4\right)=\dfrac{3}{2}\cdot\left(-4\right)^2=\dfrac{3}{2}\cdot16=\dfrac{48}{2}=24\)
=>C ko thuộc (P)
F(1/căn 2)=3/2*1/2=3/4
=>D thuộc (P)