Question

Bài 5: Phân tích đa thức sau thành nhân tử

a) x (a - b) + 2a - 2b

b) ax + by + 5x + 5y

Answer 1

\(a,x\left(a-b\right)+2a-2b=x\left(a-b\right)+2\left(a-b\right)=\left(a-b\right)\left(x+2\right)\\ b,Sửa:ax+ay+5x+5y=a\left(x+y\right)+5\left(x+y\right)=\left(a+5\right)\left(x+y\right)\)

Answer 2

\(a,=\left(x+2\right)\left(a-b\right)\\ b,Sửa:ax+ay+5x+5y\\ =a\left(x+y\right)+5\left(x+y\right)\\ =\left(a+5\right)\left(x+y\right)\)

Answer 3

a) \(x\left(a-b\right)+2a-2b\)

\(=x\left(a-b\right)+\left(2a-2b\right)\)

\(=x\left(a-b\right)+2\left(a-b\right)\)

\(=\left(a-b\right)\left(x+2\right)\)

Answer 4

a) \(x\left(a-b\right)+2a-2b=x\left(a-b\right)+2\left(a-b\right)=\left(x+2\right)\left(a-b\right)\)

 

Answer 5

a,x(a−b)+2a−2b=x(a−b)+2(a−b)=(a−b)(x+2)

b,Sửa:ax+ay+5x+5y=a(x+y)+5(x+y)=(a+5)(x+y)

Answer 6

a,x(a−b)+2a−2b=x(a−b)+2(a−b)=(a−b)(x+2)

b,Sửa:ax+ay+5x+5y=a(x+y)+5(x+y)=(a+5)(x+y)a,x(a−b)+2a−2b=x(a−b)+2(a−b)=(a−b)(x+2)b,Sửa:ax+ay+5x+5y=a(x+y)+5(x+y)=(a+5)(x+y)