\(\frac{x+2}{-18}=\frac{-8}{x+2}\)
<=> (x+2)2 = 144
<=> \(\left[\begin{array}{nghiempt}\left(x+2\right)^2=12^2\\\left(x+2\right)^2=\left(-12\right)^2\end{array}\right.\)
<=> \(\left[\begin{array}{nghiempt}x+2=12\\x+2=-12\end{array}\right.\)
<=> \(\left[\begin{array}{nghiempt}x=10\\x=-14\end{array}\right.\)
\(\frac{x-1}{x-5}=\frac{6}{7}\)
\(\Leftrightarrow7\left(x-1\right)=6\left(x-5\right)\)
\(\Leftrightarrow7x-7=6x-30\)
\(\Leftrightarrow x=-23\)
\(\frac{x-1}{x-5}=\frac{6}{7}\)
\(\Rightarrow7\left(x-1\right)=6\left(x-5\right)\)
\(\Rightarrow7x-7=6x-30\)
\(\Rightarrow7x-6x=-30+7\)
\(\Rightarrow x=-23\)
Vậy \(x=-23\)
