Question

bài 2: rút gọn

a) \(\dfrac{3+\sqrt{3}}{\sqrt{3}}+\dfrac{\sqrt{6}-\sqrt{3}}{1-\sqrt{2}}\)

b) \(\sqrt{\dfrac{x-2\sqrt{x}+1}{x+2\sqrt{x}+1}}\) (x\(\ge\) 0

c) \(\dfrac{x-y}{\sqrt{y}-1}\sqrt{\dfrac{\left(y-2\sqrt{x}+1\right)^2}{\left(x-1\right)^4}}\) x \(\ne\) 1; y \(\ne\)1 ; y \(\ge\)0

Answer 1

Đề câu c co bị sai ko vậy bạn? (y - 2\(\sqrt{x}\) +1)

Answer 2

a: \(=\sqrt{3}+1-\sqrt{3}=1\)

b: \(=\sqrt{\dfrac{\left(\sqrt{x}-1\right)^2}{\left(\sqrt{x}+1\right)^2}}=\dfrac{\left|\sqrt{x}-1\right|}{\sqrt{x}+1}\)

c: Sửa đề:\(\dfrac{x-1}{\sqrt{y}-1}\cdot\sqrt{\dfrac{y-2\sqrt{y}+1}{\left(x-1\right)^4}}\)

\(=\dfrac{x-1}{\sqrt{y}-1}\cdot\dfrac{\sqrt{y}-1}{\left(x-1\right)^2}=\dfrac{1}{\left(x-1\right)}\)