\(a,sin^2A=sinB.sinC\)
\(\Leftrightarrow\frac{a^2}{4R^2}=\frac{b}{2R}.\frac{c}{2R}\)
\(\Leftrightarrow\frac{a^2}{4R}=\frac{bc}{4R^2}\Leftrightarrow a^2=bc\)
b, Áp dụng định lý cos:
\(CosA=\frac{b^2+c^2-a^2}{2bc}=\frac{b^2+c^2-bc}{2bc}\ge\frac{2bc-bc}{2bc}=-\frac{1}{2}\)