a,Ta có \(\left(3^3\right)^n:3^n=9\Leftrightarrow3^{3n}:3^n=3^2\Leftrightarrow3n-n=2\Leftrightarrow n=1\)
b,TA có \(\dfrac{5^2}{5^n}=5^1\Leftrightarrow2-n=1\Leftrightarrow n=1\)
Các câu sau để bn tự làm
a) 27n : 3n = 9
\(\Leftrightarrow\) (27 : 3)n = 9
\(\Leftrightarrow\) 9n = 9
\(\Leftrightarrow\) n = 1
b) \(\dfrac{25}{5^n}=5\)
\(\Leftrightarrow\dfrac{5^2}{5^n}=5\)
\(\Leftrightarrow5^n.5=5^2\)
\(\Leftrightarrow5^{n+1}=5^2\)
\(\Leftrightarrow n+1=2\)
n = 2 - 1
n = 1
c) \(\dfrac{81}{\left(-3\right)^n}=-243\)
\(\Leftrightarrow\dfrac{\left(-3\right)^4}{\left(-3\right)^n}=\left(-3\right)^5\)
\(\Leftrightarrow\left(-3\right)^n.\left(-3\right)^5=\left(-3\right)^4\)
\(\Leftrightarrow\left(-3\right)^{n+5}=\left(-3\right)^4\)
\(\Leftrightarrow n+5=4\)
n = 4 - 5
n = -1