Ta có : 3x2 - 7xy + 4y2 = 0
=> 3x2 - 3xy - 4xy + 4y2 = 0
=> 3x( x - y) - 4y( x - y) = 0
=> ( x - y)( 3x - 4y) = 0
=> x = y ; 3x = 4y
Thay : x = y ; 3x = 4y vào phân thức trên ta có:
\(A=\dfrac{4y+2x}{5y-7x}+\dfrac{3x-2y}{10y-4x}\)
\(A=\dfrac{3x+2x}{5x-7x}+\dfrac{4y-2y}{10x-4x}\)
\(A=\dfrac{5x}{-2x}+\dfrac{2y}{6x}=\dfrac{5}{-2}+\dfrac{1}{3}=\dfrac{-13}{6}\)