a) Ta có: \(x^3+8\)
\(=x^3+2^3\)
\(=\left(x+2\right)\left(x^2-2x+4\right)\)
b) Ta có: \(27-8y^3\)
\(=3^3-\left(2y\right)^3\)
\(=\left(3-2y\right)\left(9+6y+4y^2\right)\)
a) \(x^3+8=x^3+2^3=\left(x+2\right)\left(x^2-2x+4\right)\)
b) \(27-8y^3=3^3-\left(2y\right)^3=\left(3-2y\right)\left(9+6y+4y^2\right)\)
c) \(\left(x-2\right)^3=\left(x-2\right)\left(x-2\right)\left(x-2\right)\)
d) \(\left(x+1\right)^3=\left(x+1\right)\left(x+1\right)\left(x+1\right)\)
P/s: Câu e, f đã biến đổi rồi mà bạn