Question

A=\(\frac{\sqrt{x}}{\sqrt{x}-1}-\frac{2}{\sqrt{x}+1}-\frac{2}{x-1}\)

Answer 1

A=\(\frac{\sqrt{x}}{\sqrt[]{x}-1}-\frac{2}{\sqrt{x}+1}-\frac{2}{x-1}\)

<=> \(\frac{\sqrt{x}\left(\sqrt{x}+1\right)-2\left(\sqrt{x}-1\right)-2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

<=> \(\frac{x+\sqrt{x}-2\sqrt{x}+2-2}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

<=> \(\frac{x-\sqrt{x}}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

<=>\(\frac{\sqrt{x}\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

=\(\frac{\sqrt{x}}{\sqrt{x}+1}\)

Chúc bạn học tốt

Answer 2

a, Rút gọn A

b,Tính gt của bt A khi x=16

c, CM A<1