a \(=9x^2-6x+1+2012\)
\(=\left(3x-1\right)^2+2012\)
\(=200000^2+2012\)
b: \(=2014^2-2\cdot2014\cdot1014+1014^2\)
\(=\left(2014-1014\right)^2=1000^2=10^6\)
c: \(x^2+3y^2=4xy\)
=>x^2-4xy+3y^2=0
=>(x-y)*(x-3y)=0
=>x=y hoặc x=3y
KHi x=y thì \(C=\dfrac{2x+2013x}{x-2x}=-2015\)
Khi x=3y thì \(C=\dfrac{6y+2013y}{3y-2y}=2019\)