Bài 4: Liên hệ giữa phép chia và phép khai phương
Các câu hỏi tương tự
a.\(\sqrt{2}.x-\sqrt{50}=0\)
b.\(\sqrt{3}.x+\sqrt{3}=\sqrt{12}+\sqrt{27}\)
c.\(\sqrt{3}.x^2-\sqrt{12}=0\)
d.\(\dfrac{x^2}{\sqrt{5}}-\sqrt{20}=0\)
Giải phương trình:
a. \(\sqrt{2}.x-\sqrt{50}=0;\) b. \(\sqrt{3}.x+\sqrt{3}=\sqrt{12}+\sqrt{27};\)
c. \(\sqrt{3}.x^2-\sqrt{12}=0;\) d. \(\dfrac{x^2}{\sqrt{5}}-\sqrt{20}=0.\)
Tính:
a) \(\sqrt{8\sqrt{3}}-2\sqrt{25\sqrt{12}}+4\sqrt{\sqrt{192}}\)
b) \(\dfrac{10+2\sqrt{10}}{\sqrt{5}+\sqrt{2}}+\dfrac{8}{1-\sqrt{5}}\)
c) \(\dfrac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\dfrac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)
tính:a) sqrt{dfrac{1}{8}}.sqrt{2}.sqrt{125}.sqrt{dfrac{1}{5}}b)sqrt{sqrt{2}-1}.sqrt{sqrt{2}+1}c) sqrt{11-6sqrt{2}}.sqrt{11+6sqrt{2}}d) sqrt{12-6sqrt{3}}.sqrt{dfrac{1}{3-sqrt{3}}}e) dfrac{sqrt{15}-sqrt{6}}{sqrt{35}-sqrt{14}}f) dfrac{2sqrt{15}-2sqrt{10}+sqrt{6}-3}{2sqrt{5}-2sqrt{10}-sqrt{3}+sqrt{6}}g) left(dfrac{1}{5-2sqrt{6}}+dfrac{2}{5+2sqrt{6}}right)left(15+2sqrt{6}right)
Đọc tiếp
tính:
a) \(\sqrt{\dfrac{1}{8}}.\sqrt{2}.\sqrt{125}.\sqrt{\dfrac{1}{5}}\)
b)\(\sqrt{\sqrt{2}-1}.\sqrt{\sqrt{2}+1}\)
c) \(\sqrt{11-6\sqrt{2}}.\sqrt{11+6\sqrt{2}}\)
d) \(\sqrt{12-6\sqrt{3}}.\sqrt{\dfrac{1}{3-\sqrt{3}}}\)
e) \(\dfrac{\sqrt{15}-\sqrt{6}}{\sqrt{35}-\sqrt{14}}\)
f) \(\dfrac{2\sqrt{15}-2\sqrt{10}+\sqrt{6}-3}{2\sqrt{5}-2\sqrt{10}-\sqrt{3}+\sqrt{6}}\)
g) \(\left(\dfrac{1}{5-2\sqrt{6}}+\dfrac{2}{5+2\sqrt{6}}\right)\left(15+2\sqrt{6}\right)\)
bài 1 : giải pt
a,sqrt{dfrac{2x^2-4x+2}{6}}1
b, dfrac{6}{x-4}sqrt{2}
c,sqrt{dfrac{20}{2x^2-8x+8}}sqrt{5}
bài 2 : tính
a, sqrt{3+sqrt{5}}-sqrt{3-sqrt{5}}-sqrt{2}
b,left(sqrt{12}+sqrt{75}+sqrt{27}right):sqrt{15}
c, left(12sqrt{20}-8sqrt{200}+7sqrt{450}right):sqrt{10}
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bài 1 : giải pt
a,\(\sqrt{\dfrac{2x^2-4x+2}{6}}=1\)
b, \(\dfrac{6}{x-4}=\sqrt{2}\)
c,\(\sqrt{\dfrac{20}{2x^2-8x+8}}=\sqrt{5}\)
bài 2 : tính
a, \(\sqrt{3+\sqrt{5}}-\sqrt{3-\sqrt{5}}-\sqrt{2}\)
b,\(\left(\sqrt{12}+\sqrt{75}+\sqrt{27}\right):\sqrt{15}\)
c, \(\left(12\sqrt{20}-8\sqrt{200}+7\sqrt{450}\right):\sqrt{10}\)
Tính
a,(√5+√3+1)×(√5-1)
b,(5-2√3)×(5+2√3)
c,1/3×√15:3/4×√3×4√2×7√10
d,(10√48-6√27+4√12):√3
Rút gọn các biểu thức
A= \(\sqrt{\left(\sqrt{2}-1\right)^2}\)-\(\sqrt{3+2\sqrt{2}}\)
B= \(\sqrt{6+2\sqrt{5}-\sqrt{29-12\sqrt{5}}}\)
C= \(\sqrt{\left(2\sqrt{5}-7\right)^2}\)-\(\sqrt{45-20\sqrt{5}}\)
D= \(\sqrt{\left(3-\sqrt{5}\right)^2}\)+\(\sqrt{5}\)
B4: Rút gọn biểu thức:
a, \(\dfrac{x^2}{y^2}\div\sqrt{\dfrac{x^2}{y^4}}\) với x,y \(\ne\) 0
b, \(\sqrt{\dfrac{27(x-1)^2}{12}}+\dfrac{3}{2}-(x-2)\sqrt{\dfrac{50x^2}{8(x-2)^2}}\) với 1<x<2
tính : b, \(\left(\dfrac{\sqrt{4}}{3}-\sqrt{3}+\dfrac{\sqrt{25}}{3}\right)\times\sqrt{12}\)
a, \(\dfrac{\sqrt{2}}{98}\)