\(A=1+\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2014}}\)
\(\Rightarrow2A=2+1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2013}}\)
\(\Rightarrow2A-A=\left(2+1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2013}}\right)-\left(1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2014}}\right)\)
\(\Rightarrow A=2-\dfrac{1}{2^{2014}}\)
\(\Rightarrow A=\dfrac{2^{2015}-1}{2^{2014}}\)
Câu 1. Cho A=\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{2012^2}\). So sánh A và 1.
Câu 2. Tính \(A=2014+\dfrac{2014}{1+2}+\dfrac{2014}{1+2+3}+\dfrac{2014}{1+2+3+4}+...+\dfrac{2014}{1+2+3+4+...+2013}\)
Câu 3. Cho A=\(\dfrac{6n+42}{6n}\)với n \(\in\) Z và n \(\ne\) 0. Tìm tất cả các số nguyên n sao cho A cũng là số nguyên.
Câu 4. So sánh A=\(\dfrac{17^{18}+1}{17^{19}+1}\) và B=\(\dfrac{17^{17}+1}{17^{18}+1}\).
Cho S=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{2015^2}\). Chứng tỏ rằng \(\dfrac{1007}{2016}< S< \dfrac{2014}{2015}\)
Cho \(A=\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+\dfrac{1}{3\cdot4\cdot5}+...+\dfrac{1}{2014\cdot2015\cdot2016}\).
Chứng minh \(A\le\dfrac{1}{4}\).
Cho \(A=\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+\dfrac{1}{3\cdot4\cdot5}+...+\dfrac{1}{2014\cdot2015\cdot2016}\).
So sánh A với \(\dfrac{1}{4}\).
a, \(\left(1+\dfrac{1}{2}\right)\left(1+\dfrac{1}{2^2}\right)\left(1+\dfrac{1}{2^3}\right)\left(1+\dfrac{1}{2^4}\right)....\left(1+\dfrac{1}{2^{50}}\right)< 3\)
b, \(\dfrac{1}{2}-\dfrac{1}{2^2}+.........+\dfrac{1}{2^{99}}-\dfrac{1}{2^{100}}< \dfrac{1}{3}\)
A=\(\dfrac{1}{1^2}+\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{50^2}\)
GIÚP BÉ VỚI Ạ! ĐANG CẦN GẤP 
Cho A = \(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}.CT:\dfrac{8}{9}>A>\dfrac{2}{5}\)
Cho A = \(\dfrac{\left(3\dfrac{2}{15}+\dfrac{1}{5}\right):2\dfrac{1}{2}}{\left(5\dfrac{3}{7}-2\dfrac{1}{4}\right):4\dfrac{43}{56}}\) ; B = \(\dfrac{1,2:\left(1\dfrac{1}{5}.1\dfrac{1}{4}\right)}{0,32+\dfrac{2}{25}}\)
Chứng minh rằng A= B
\(a,\dfrac{\dfrac{3}{41}-\dfrac{12}{47}+\dfrac{27}{53}}{\dfrac{4}{41}-\dfrac{16}{47}+\dfrac{36}{53}}+\dfrac{-0,25.\dfrac{-2}{3}-75\%:\left(\dfrac{-1}{2}+\dfrac{2}{3}\right)}{\left|-1\dfrac{1}{2}\right|.\left(\dfrac{-2}{3}-0,75:\dfrac{3}{-2}\right)}\)
