\(x\ge10\)
\(\frac{x!}{\left(x-10\right)!}+\frac{x!}{\left(x-9\right)!}=\frac{9x!}{\left(x-8\right)!}\)
\(\Leftrightarrow1+\frac{1}{x-10}=\frac{9}{\left(x-10\right)\left(x-9\right)}\)
\(\Rightarrow\left(x-10\right)\left(x-9\right)+x-9=9\)
\(\Leftrightarrow x^2-18x+72=0\Rightarrow\left[{}\begin{matrix}x=6\left(l\right)\\x=12\end{matrix}\right.\)