Question

a, \(|x+\dfrac{3}{4}|-\dfrac{1}{3}=0\)

b, áp dụng tính chất : x < y và y < z thì x < z

\(\dfrac{13}{38}\)và\(\dfrac{-12}{-37}\)

Giúp mình nha

Answer 1

a/ \(\left|x+\dfrac{3}{4}\right|-\dfrac{1}{3}=0\)

\(\Leftrightarrow\left|x+\dfrac{3}{4}\right|=\dfrac{1}{3}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=\dfrac{1}{3}\\x+\dfrac{3}{4}=-\dfrac{1}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{5}{12}\\x=-\dfrac{13}{12}\end{matrix}\right.\)

Vậy ..............

b, \(\dfrac{-12}{-37}=\dfrac{12}{37}< \dfrac{12}{36}=\dfrac{13}{39}< \dfrac{13}{38}\)

\(\Leftrightarrow\dfrac{13}{38}>\dfrac{-12}{-37}\)

Answer 2

a)\(\text{|}x+\dfrac{3}{4}\text{|}-\dfrac{1}{3}=0\)

=>\(\text{|}x+\dfrac{3}{4}\text{|}=\dfrac{1}{3}\)

=>\(x+\dfrac{3}{4}=-\dfrac{1}{3}\)hoặc\(x+\dfrac{3}{4}=\dfrac{1}{3}\)

=>\(x=-\dfrac{13}{12}\)hoặc\(x=-\dfrac{5}{12}\)

Vậy...

b)\(\dfrac{13}{38}\) và \(\dfrac{-12}{-37}\)

Ta có:\(\dfrac{-12}{-37}=\dfrac{12}{37}< \dfrac{12}{36}=\dfrac{1}{3}=\dfrac{13}{39}< \dfrac{13}{38}\)

=>\(\dfrac{13}{38}>\dfrac{-12}{-37}\)