pt đã cho \(\Leftrightarrow\left(a+b\right)x^2+\left(a+2b\right)x+\left(2a-3b\right)=-x^2-6x+23\)
\(\Rightarrow\left\{{}\begin{matrix}a+b=-1\\a+2b=-6\\2a-3b=23\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}a=4\\b=-5\end{matrix}\right.\)
Kl: a=4, b=-5