a) \(\left(x-4\right)\left(x+4\right)-x\left(x+2\right)=10\)
<=> \(x^2-16-x^2-2x=10\)
<=> \(-16-2x-10=0\)
<=> \(x=-13\)
Vậy pt có tập nghiệm S\(\)={-13}
b) \(\frac{\left(x+3\right)}{2}-\frac{\left(x-2\right)}{3}=2-\frac{\left(x+3\right)}{2}\)
<=> \(3\left(x+3\right)-2\left(x-2\right)=2.6-3\left(x+3\right)\)
<=> \(3x+9-2x+4=12-3x-9\)
<=> \(3x+9-2x+4-12+3x+9=0\)
<=> \(4x+10=0\)
<=> \(x=\frac{-5}{2}\)
Vậy pt có tập nghiệm S={\(\frac{-5}{2}\)}
a) \(\left(x-4\right)\left(x+4\right)-x\left(x+2\right)=10\)
\(\Leftrightarrow x^2-16-x^2-2x-10=0\)
\(\Leftrightarrow-26=2x\Leftrightarrow x=\frac{-26}{2}=-13\)
b) \(\frac{\left(x+3\right)}{2}-\frac{\left(x-2\right)}{3}=2-\frac{\left(x+3\right)}{2}\)
\(\Leftrightarrow\left(\frac{3\left(x+3\right)-2\left(x-2\right)}{6}\right)=\frac{12-3\left(x+3\right)}{6}\)
\(\Leftrightarrow3x+9-2x+4=12-3x-9\)
\(\Leftrightarrow x+13=-3x+3\)
\(\Leftrightarrow x+3x=-13+3\)
\(\Leftrightarrow4x=-10\Leftrightarrow x=\frac{-10}{4}=-2,5\)
a ) \(\left(x-4\right)\left(x+4\right)-x\left(x+2\right)=10\)
\(\Leftrightarrow x^2-16-x^2-2x=10\)
\(\Leftrightarrow-2x=26\)
\(\Leftrightarrow x=-13\)
Vậy \(x=-13.\)
b ) \(\frac{\left(x+3\right)}{2}-\frac{\left(x-2\right)}{3}=2-\frac{\left(x+3\right)}{2}\)
\(\Leftrightarrow\frac{3\left(x+3\right)}{6}-\frac{2\left(x-2\right)}{6}=\frac{12}{6}-\frac{3\left(x+3\right)}{6}\)
\(\Leftrightarrow3x+9-2x-4=12-3x+9\)
\(\Leftrightarrow3x-2x+3x=12+9-9+4\)
\(\Leftrightarrow4x=16\)
\(\Leftrightarrow x=4\)
Vậy \(x=4.\)
Mình sửa lại nha :)
a ) \(\left(x-4\right)\left(x+4\right)-x\left(x+2\right)=10\)
\(\Leftrightarrow x^2-16-x^2-2x=10\)
\(\Leftrightarrow-2x=26\)
\(\Leftrightarrow x=-13\)
Vậy \(x=-13\)
b ) \(\frac{\left(x+3\right)}{2}-\frac{\left(x-2\right)}{3}=2-\frac{\left(x+3\right)}{2}\)
\(\Leftrightarrow3\left(x+3\right)-2\left(x-2\right)=12-3\left(x+3\right)\)
\(\Leftrightarrow3x+9-2x+4=12-3x-9\)
\(\Leftrightarrow4x+10=0\)
\(\Leftrightarrow x=-\frac{5}{2}\)
Vậy \(x=-\frac{5}{2}.\)
a, (x-4)(x+4) - x(x+2) = 10
<=> ( x2 - 42) - x2 - 2x = 10
<=> x2 - 16 - x2 - 2x = 10
<=> - 16 - 2x = 10
<=> -2x = 10 + 16
<=> -2x = 26
<=> x = -13
b, \(\frac{\left(x+3\right)}{2}\) - \(\frac{\left(x-2\right)}{3}\) = 2 - \(\frac{x+3}{2}\)
<=> \(\frac{3.\left(x-3\right)}{6}\)- \(\frac{2.\left(x-2\right)}{6}\) = \(\frac{12}{6}\) - \(\frac{3.\left(x+3\right)}{6}\)
=> 3.(x-3) - 2.(x-2) = 12 - 3.(x+3)
<=> 3x - 3 -2x + 4 = 12- 3x - 9
<=> 3x - 2x + 3x = 3-4+12-9
<=> 4x = 2
<=> x = \(\frac{1}{2}\)
CHÚC BN HK TỐT
TICK MK NHA
