Tìm x
1) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^6\) 2) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^{36}\) 3) \(\left(\dfrac{1}{81}\right)^x=\left(\dfrac{1}{27}\right)^4\)
4) \(\left(\dfrac{4}{9}\right)^x=\left(\dfrac{8}{27}\right)^{10}\) 5) \(2^x=4^5.4^3\) help me !!!!
Bài 4.1: Tìm x, biết
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x-9\right|=5\)
c) \(\left|2\frac{1}{5}-x\right|+\left|x-\frac{1}{5}\right|+8\frac{1}{5}=1,2\)
d) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
Tìm giá trị nhỏ nhất của biểu thức :
a) A=\(\left|x+2\right|+\left|2x-3\right|+\left|x-5\right|\)
b) B=\(\left|x+2\right|+\left|3x-1\right|+\left|x-7\right|+5\)
c) C=\(\left|x+1\right|+4\left|2x-7\right|+\left|x-5\right|\)
d) D=\(\left|x+4\right|+5\left|x+1\right|+\left|x-2\right|+5\)
Tìm x biết :
1. \(\sqrt{x-1}=2\)
2. \(\sqrt{3-x}=1\)
3. \(\left|x-1\right|+\left|x^2-1\right|=0\)
4. \(\left|2x-3\right|-\left|x-1\right|=0\)
Help me!! Thanks for helping !!
a) \(\left(x-2\right)\left(x+1\right)< 0\)
b) \(\left(x+\dfrac{1}{3}\right)\left(x-1\right)\)> hoặc = 0
Bài 1 : Tìm x biết :
a) \(3\left|x-1\right|+3\left|3x-5\right|=2\) b)\(\left|x+2\right|+\left|2x-1\right|+\left|5x-15\right|=10\)
Bài 2 :
a)\(\left|6x-9\right|+\left|9x-33\right|=13\) b)\(\left|x+1\right|+\left|3x-2\right|+\left|6x-24\right|=15\)
\(\left|x+\frac{1}{2}\right|+\left|x+\frac{1}{6}\right|+\left|x+\frac{1}{12}\right|+\left|x=\frac{1}{20}\right|+...+\left|x+\frac{1}{101}\right|=101x\)
2. Tìm x, y, z biết\(\left(2x+1\right)^{2008}+\left(y-\frac{2}{5}\right)^{2008}+\left|x+y+z\right|=0\)
3.Tìm x\(a,2009-\left|x-2009\right|=x\)
\(b,\left|3x+2\right|=\left|5x-3\right|\)
Tìm x,y
\(\left(x-1\right)^2+\left(y-2\right)^2=0\)
HELP ME <> SẼ TICK
Tìm x, biết:
a) \(\left(5x+1\right)^2=\dfrac{36}{49}\)
b) \(\left[\left(-0,5\right)^3\right]^x=\dfrac{1}{64}\)
c) \(2020^{\left(x-2\right).\left(2x+3\right)}=1\)
d) \(\left(x+1\right)^{x+10}=\left(x+1\right)^{x+4}\) với \(x\in Z\)
e) \(\dfrac{3}{4}\sqrt{x}-\dfrac{1}{2}=\dfrac{1}{3}\)