a: Ta có: \(\left(x-2\right)\left(x+1\right)< 0\)
\(\Leftrightarrow-1< x< 2\)
b: Ta có: \(\left(x+\dfrac{1}{3}\right)\left(x-1\right)\ge0\)
\(\Leftrightarrow\left[{}\begin{matrix}x\le-\dfrac{1}{3}\\x\ge1\end{matrix}\right.\)
a: Ta có: \(\left(x-2\right)\left(x+1\right)< 0\)
\(\Leftrightarrow-1< x< 2\)
b: Ta có: \(\left(x+\dfrac{1}{3}\right)\left(x-1\right)\ge0\)
\(\Leftrightarrow\left[{}\begin{matrix}x\le-\dfrac{1}{3}\\x\ge1\end{matrix}\right.\)
Tìm x biết
a,\(\left|x-\dfrac{1}{3}\right|+\dfrac{4}{5}=\left|\left(-3,2\right)+\dfrac{2}{5}\right|b,\left(x-7\right)^{x+1}+\left(x-7\right)^{x+11}=0\)
Bài 1:
a)\(\left|x-2\right|\)+\(\left|1-\dfrac{x}{2}\right|\)=0 b)\(\left(x-\dfrac{1}{3}\right)^3\)=\(\dfrac{-8}{27}\)
c)\(\dfrac{x^2}{6}\)=\(\dfrac{24}{25}\) c)\(\dfrac{x-1}{x+5}\)=\(\dfrac{6}{7}\)
Giúp mik làm bài này với ạ mik đang cần gấp tối nay mik phải nộp rồi mong mn giúp đỡ mik. Mik cảm ơn mn
Câu 1:
a) \(\left|\left|3x-3\right|+2x+\left(-1\right)^{2016}\right|=3x+2017^0\)
b) Cho B = \(1+\dfrac{1}{2}.\left(1+2\right)+\dfrac{1}{3}.\left(1+2+3\right)+....+\dfrac{1}{x}.\left(1+2+3+...+4\right)=115\)(x thuộc số tự nhiên khác 0)
Tìm y biết:
a) 2y . (y - \(\dfrac{1}{7}\)) = 0
b) \(-\dfrac{2}{5}+\dfrac{2}{3}y+\dfrac{1}{6}y=\dfrac{-4}{15}\)
Tìm các số x thỏa mãn:
a) \(x.\left(x-\dfrac{4}{7}\right)>0\)
b)\(\left(x-\dfrac{2}{5}x^2\right)< 0\)
c)\(\left(x-\dfrac{2}{5}\right).\left(x+\dfrac{3}{7}\right)>0\)
d)\(\left(x-\dfrac{2}{5}\right).\left(x+\dfrac{3}{7}\right).\left(x+\dfrac{3}{4}\right)>0\)
(* dấu . là dấu nhân nha bạn ^-^)
Tìm x \(\in\) Q biết:
a)\(\left|2,5-x\right|-1,3=0\)
b)\(1,6\cdot\left|x-0,2\right|=0\)
c)\(\left|\dfrac{1}{3}-x\right|-\left|\dfrac{-3}{7}\right|=0\)
d)\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
e)\(\left|x-1,5\right|+\left|2,5-x\right|=0\)
1) tìm x:
\(\left(\dfrac{1}{7}x-\dfrac{2}{7}\right)\left(-\dfrac{1}{5}x+\dfrac{3}{5}\right)\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)=0\)
Tìm x, biết:
a) \(\left(5x+1\right)^2=\dfrac{36}{49}\)
b) \(\left[\left(-0,5\right)^3\right]^x=\dfrac{1}{64}\)
c) \(2020^{\left(x-2\right).\left(2x+3\right)}=1\)
d) \(\left(x+1\right)^{x+10}=\left(x+1\right)^{x+4}\) với \(x\in Z\)
e) \(\dfrac{3}{4}\sqrt{x}-\dfrac{1}{2}=\dfrac{1}{3}\)
Bài 1: Tìm x, biết :
a, \(\dfrac{11}{13}\) - \((\dfrac{5}{42}\) - x \()\) = - \((\)\(\dfrac{15}{28}\)- \(\dfrac{11}{15}\)\()\)
b, \(|x+\dfrac{4}{15}|\) - \(|-3,75|\)= - \(\left|-2,15\right|\)
c, \(\dfrac{5}{3}\) - \(\left|x-\dfrac{3}{2}\right|\) = \(\dfrac{-1}{2}\)
d,\(\left(x-\dfrac{2}{3}\right)\). \(\left(2x-\dfrac{3}{2}\right)\) = 0
BÀi 3: Tìm x,y biết
a, \(\left(x^2-4\right)^2\)+ \(\left(x+2^{ }\right)\)\(^2\) = 0
b, \(\left(x-y^{ }\right)^2\) + \(\left|y+2\right|\) = 0
c, \(\left|x-y\right|\)+ \(\left|y+\dfrac{9}{25}\right|\)= 0
d, \(\left|\dfrac{1}{2}-\dfrac{1}{3}+x\right|\)= \(\left(-\dfrac{1}{4}\right)\)- \(\left|y\right|\)
a)tìm các cặp số nguyên x;y thỏa mãn (2x-)(x+1)=|y+1|
b)\(\left|x+\dfrac{1}{1.3}\right|+\left|x+\dfrac{1}{3.5}\right|+\left|x+\dfrac{1}{5.7}\right|+...+\left|x+\dfrac{1}{97.99}\right|=50x\)
cho A=\(\left(\dfrac{1}{2^2}-1\right).\left(\dfrac{1}{3^2}-1\right).\left(\dfrac{1}{4^2}-1\right)...\left(\dfrac{1}{100^2}-1\right)\)hãy so sánh A với \(\dfrac{-1}{2}\)