Question

9x²-6x+1=0

Answer 1

Ta có:

\(9x^2-6x+1=0\)

\(\Leftrightarrow\left(3x-1\right)^2=0\)

\(\Leftrightarrow3x-1=0\)

\(\Leftrightarrow3x=1\)

\(\Leftrightarrow x=\dfrac{1}{3}\)

Vậy để \(9x^2-6x+1=0\) thì \(x=\dfrac{1}{3}\)

Answer 2

\(9x^2-6x+1=0\)

\(\Leftrightarrow\left(3x\right)^2-2.3.x+1^2=0\)

\(\Leftrightarrow\left(3x-1\right)^2=0\)

\(\Rightarrow3x-1=0\)

\(\Rightarrow3x=1\)

\(\Rightarrow x=\dfrac{1}{3}\)